21^2+21x=96x-36

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Solution for 21^2+21x=96x-36 equation:



21^2+21x=96x-36
We move all terms to the left:
21^2+21x-(96x-36)=0
We add all the numbers together, and all the variables
21x-(96x-36)+441=0
We get rid of parentheses
21x-96x+36+441=0
We add all the numbers together, and all the variables
-75x+477=0
We move all terms containing x to the left, all other terms to the right
-75x=-477
x=-477/-75
x=6+9/25

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